Table of Contents

EP-ROCK

Description

Constitutive law for layered rocks at constant temperature

The model

This law is only used for elasto‑plastic constitutive law for mechanical analysis of layered rocks, with only one family of parallel joints. Rocks are elastic and joints have a COULOMB rigid plastic behaviour.

Files

Prepro: LROCK.F
Lagamine: ELP1.F (2D), ELP3DT.F (3D)

Availability

Plane stress state NO
Plane strain state YES
Axisymmetric state NO
3D state YES (?)
Generalized plane state NO

Input file

Parameters defining the type of constitutive law

Line 1 (2I5, 60A1)
ILLaw number
ITYPE 10
COMMENT Any comment (up to 60 characters) that will be reproduced on the output listing

Integer parameters

Line 1 (I5)
NINTVnumber of sub‑steps used to integrate numerically the constitutive equation in a time step.

Real parameters

Line 1 (6G10.0)
EYoung's elastic modulus
ANUPoisson's ratio
COmaterial cohesion between layers
FIfriction angle (in degrees) between layers
STstratigraphy angle (in degrees), that is the angle of the layers with respect to an horizontal plane
PSIdilatancy angle (in degrees)

Stresses

Number of stresses

= 6 for the 3-D state
= 4 for the other cases.

Meaning

The stresses are the components of CAUCHY stress tensor in global (X, Y, Z) coordinates. For the 3-D state :

SIG(1)$\sigma_{xx}$
SIG(2)$\sigma_{yy}$
SIG(3)$\sigma_{zz}$
SIG(4)$\sigma_{xy}$
SIG(5)$\sigma_{xz}$
SIG(6)$\sigma_{yz}$

For the other cases :

SIG(1)$\sigma_{xx}$
SIG(2)$\sigma_{yy}$
SIG(3)$\sigma_{xy}$
SIG(4)$\sigma_{zz}$

State variables

Number of state variables

2

List of state variables

Q(1)= element thickness (t) in plane stress state
= 1 in plane strain state
= circumferential strain rate ($\dot{\varepsilon}_\theta$) in axisymmetrical state
= 0 in 3‑D state
= element thickness (t) in generalized plane state.
Q(2)= 0 if the current state is elastic
= 1 if the current state in elasto‑plastic (i.e., sliding between joints has occurred)