====== BINDS ====== ===== Description ===== These elements are used to impose a linear relationship between the DOF of some nodes\\ They must refer to the material law [[laws:binds|BINDS]] (ITYPE= 30)\\ Element type: 99\\ Implemented by: Bertarini I. (1986) & revised by Pascon F. (1999)\\ Example of relationship: $\displaystyle\sum_{i=1}^{m} \alpha_i . \delta_i = \alpha_0$\\ With:\\ $\delta_i$: the degree of freedom (translation or rotation: 1, 2 ...)\\ $\alpha_i$ and $\alpha_0$: data specified in the section "COLAW" for the material: LMATE and specified in each relation\\ $m$: number of terms in the linear relationship\\ See example below\\ ==== Files ==== Prepro: BINDSA.F \\ Lagamine: BINDSB.F ===== Input file ===== ^ Title (A5)^^ |TITLE |"BINDS" | ^Control data (I5)^^ |NELEM |number of elements | ^ Definition of the elements (3I5/3*NNODE I5)^^ |LMATE |material number (type 30) | |NNODE |number of terms in the relation (max: 10) (see note 1)| |INDISO |position of $\alpha_0$ in the list of the $\alpha$ coefficients of the law LMATE | |NODES(I) |node number in the relation | |IDOF(I) |componant of the node used in the relation (1: first DOF, 2: second DOF ...) (see note 2) | |INDIS(I) |position of the $\alpha_i$ coefficient in the law LMATE | | **Note:** These 3 consecutive terms are written for I=1:NNODE on the same line|| __**Notes**__\\ 1: if NNODE >10, the subroutines: BINDSA and BINDSB must be adapted \\ 2: Number of DOF in global axes 1= displacement in X direction 2= displacement in Y direction 3= displacement in Z direction 4= rotation around the axis X 5= rotation around the axis Y 6= rotation around the axis Z 3: The $\alpha_0$ coefficient is multiplied by DMULT ===== Example ===== If you have the 2 following relations:\\ $4.U_1 + 2. V_2 - U_3 = 0$ (element n° 1) \\ $2.V_1 + 2. U_2 + 4.U_3 = 4$ (element n° 2)\\ where, for example, $U_3$ is related to the first DOF (U) of the node 3\\ You have to describe 1 law with all the $\alpha_i$ coefficients:\\ $\alpha_1$= 4\\ $\alpha_2$= 2\\ $\alpha_3$= -1\\ $\alpha_4$= 0\\ And you have to define 1 element for each relation (here: 2 elements) \\ After the title, you have 5 lines: \\ ^ Line 1^ |NELEM = 2| __**First element:**__ ^Line 2^^^ |LMATE = law nb.|NNODE = 3 |INDISO = 4| ^Line 3^^^^^^^^^ |NODES(1) = 1 | IDOF(1) = 1 | INDIS(1) = 1 |NODES(2) = 2 |IDOF(2) = 2| INDIS(2) = 2|NODES(3) = 3 |IDOF(3) = 1 |INDIS(3) = 3 | | for $4.U_1$ ||| for $2.V_2$ ||| for $-U_3$ ||| __**Second element:**__ ^Line 4^^^ |LMATE = law nb. |NNODE = 3 |INDISO = 1 | ^Line 5^^^^^^^^^ |NODES(1) = 1 |IDOF(1) = 2 |INDIS(1) = 2 | NODES(2) = 2 |IDOF(2) = 1 |INDIS(2) = 2 | NODES(3) = 3 |IDOF(3) = 1 |INDIS(3) = 1 | | for $2.V_1$ ||| for $2.U_2$ ||| for $4.U_3$ ||| ===== Results ===== Effort in the spring